Answer:d
Step-by-step explanation:
Given
Temperature

Also

R=287 J/kg
Flow will be In-compressible when Mach no.<0.32
Mach no.

(a)

Mach no.

Mach no.=0.63
(b)

Mach no.

Mach no.=0.31
(c)

Mach no.

Mach no.=1.27
(d)

Mach no.

Mach no.=0.127
From above results it is clear that for Flow at velocity 200 km/h ,it will be incompressible.