Question

What is the pH of a 0.05 M solution of TRIS
acid(pKa = 8.3)?

Answer 1

pH of the solution = 4.80

Step-by-step explanation:

pKa = 8.3

Concentration of tris acid = 8.3

`pH = (1)/(2) * p_(ka) - (1)/(2) logC`

`pH = (1)/(2) * 8.3 - (1)/(2)* log(0.05)`

`= (1)/(2) * 8.3 - (1)/(2)* log(5* 10^(-2))`

`= 4.15 - (1)/(2)* (-1.30103)`

`= 4.15 - (-0.650515)`

`= 4.15 + 0.650515`

= 4.80

pH of the solution = 4.80