Answer: 21
Explanation:
Given : A bag containing five red marbles, two green ones, one transparent one, four yellow ones, and two orange ones .
Total marbles other than red or green = 1+4+2=7
Now, the number of combinations to select five marbles from the set of 7 will be :-
![7C_5=(7!)/(5!(7-5)!)=(7*6*5!)/(5!*2!)=21](https://img.qammunity.org/2020/formulas/mathematics/college/gqi56pwp3f0njkwpl7c25kuraaxlz15fal.png)
Hence, the number of possible sets of five marbles are there in which none of them are red or green =21