Question

What is the energy in joules of one photon of
microwaveradiation with a wavelength 0.122m?

Answer 1

Answer: The energy of photon is
`162.93* 10^(-26)J`

Step-by-step explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

`E=(hc)/(\lambda)`

where,

E = energy of the light = ?

h = Planck's constant =
`6.626* 10^(-34)Js`

c = speed of light =
`3* 10^8m/s`

`\lambda` = wavelength of photon = 0.122 m

Putting values in above equation, we get:

`E=((6.626* 10^(-34)Js)* (3* 10^8m/s))/(0.122m)\\\\E=162.93* 10^(-26)J`

Hence, the energy of photon is
`162.93* 10^(-26)J`