1 Answer

Nasta · Answer 1 · 2020-05-11T09:06:39+0000

Answer:

Pressure of pressure head will be
863.6pound/ft^2

Step-by-step explanation:

We have given pressure head = 14 feet

Specific weight of water
$(\rho g)_(water)=62.4pound/ft^3$

Pressure is given by
$P=(\rho g)_(water)h$ , here h is pressure head.

So pressure
$P=(\rho g)_(water)h=62.4pound/ft^3* 14ft=863.6pound/ft^2$

So the pressure of pressure head will be
863.6pound/ft^2

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