Question

35 year old female. 5’8', 220 pounds. Calculate Adjusted Body Weight. (Round to the nearest tenth if applicable): ________

Answer 1

Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.

Explanation:

To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).

We have the following formulas:

`IBW = 45.5kg + 2.3kg*i`, in which i is the number of inches that the woman has above 5 feet.

`AjBW = IBW + 0.4*(ABW - IBW)`, in which
`ABW` is her Actual Body Weight

So, in this problem:

Each pound has 0.45kg. So her weight is
`ABW = 220*0.45 = 99.8`kg.

The woman is 8 inches above 5 feet, so
`i = 8`.

`IBW = 45.5 + 2.3*8`

`IBW = 63.9`kg

Her ideal body weight is 63.9kg. Her adjusted body weight is:

`AjBW = IBW + 0.4*(ABW - IBW)`

`AjBW = 63.9 + 0.4*(99.8-63.9)`

`AjBw = 78.26`kg

Her adjusted body weight is 78.26kg = 78.3kg.