Question

A skiy diver, with parachute unopened, falls 625 m in 15.0s.

Then she opens her parachute and falls another 356 m in142 s. What
is her average velocity (both magnitude anddirection) for the
entire fall?

Answer 1

average velocity = 6.25m/sec

Step-by-step explanation:

given data:

for unopened

height = 625 m

time = 15 sec

for opened

height = 356 m

time = 142 sec

Unopened:

`V1 = (625\ m)/(15\ sec) = 41.67m/sec`

Opened:

`V2 = (356\ m)/(142\ sec) = 2.51m/sec`

we know that

Total Average Velocity
`= (Total\ distance)/(Total\ time)`

average velocity
`= (981\ m)/(157\ sec)`

average velocity = 6.25m/sec

downward direction.