Answer:
The distance of spot of light from his feet equals 3.425 meters.
Step-by-step explanation:
The situation is represented in the attached figure below
The angle of incidence is computed as
![\theta _i=tan^(-1)((1.3)/(2.7))\\\\\therefore \theta _i=25.71^(o)](https://img.qammunity.org/2020/formulas/physics/college/ha3mq651pbpnzbb6a5yhtybz0jz8z6cdur.png)
Now by Snell's law we have
![n_(i)sin(\theta _i)=n_(r)sin(\theta _r)](https://img.qammunity.org/2020/formulas/physics/college/agdk0jhja89l2l9nmg53e6bad1xi7q5szf.png)
where
are the refractive indices of the incident and the refracting medium respectively
are the angle of incidence and the angle of refraction respectively
Thus using the Snell's relation we have
![1.0* sin(25.71)=1.33* sin(\theta _r)\\\\\therefore sin(\theta _r)=(sin(25.71)/(1.33)=0.326\\\\\therefore \theta _r=sin^(-1)(0.326)=19.04^(o)](https://img.qammunity.org/2020/formulas/physics/college/zx6q0gb049id3mbjpjobw60bswhl7k6rf3.png)
from the attached figure we can see
![tan(\theta _r)=(L_(2))/(H)=(L_(2))/(2.1)\\\\\therefore L_(2)=2.1* tan(19.04)=0.725m](https://img.qammunity.org/2020/formulas/physics/college/nx6upx56bil249ev3xxp33tbzvlm4i70d0.png)
Thus distance of spot on the pool bed from his feet equals
![2.7+0.725=3.425m](https://img.qammunity.org/2020/formulas/physics/college/l5gz89h1p9r2dtr0k1s06u8igon2fx0o4a.png)