Question

A 7.0-kg bowling ball experiences a net force of 5.0 N.
Whatwill be its acceleration?

Answer 1

It will have an acceleration of
`0.71 m/s^(2)`.

Step-by-step explanation:

Newton’s second law is defined as:

`F = ma` (1)

Equation 1 can be rewritten for the case of the acceleration:

`a = (F)/(m)`

The force and the acceleration are directly proportional (if one increase the other will increase too).

`a = (5.0 N)/(7.0 Kg)`

But 1 N is equivalent to
`1 Kg.m/s^(2)`

`a = (5.0 Kg.m/s^(2))/(7.0 Kg)`

`a = 0.71 m/s^(2)`

So a body will have an acceleration as a consequence of the action of a force.