Answer:
The work done on the jet is
![W_(jet) = 2.49* 10^(7) J](https://img.qammunity.org/2020/formulas/physics/college/6fg98d2nxn7pugrsqq25tuehk5bzh1fzug.png)
Given:
Force, F =
![2.3* 10^(5) N](https://img.qammunity.org/2020/formulas/physics/college/arr43kdub44ogiw1lna458lvtd8hp4gvjb.png)
Distance moved by the jet, x = 87 m
Kinetic Energy, KE =
![4.5* 10^(7) J](https://img.qammunity.org/2020/formulas/physics/college/31430ih0w5thluijeypog7nqypz2xrita3.png)
Solution:
Now, to calculate the work done on the fire fighter jet by the catapult, we find the difference between the KE of the jet at lift off and the work done by the engines.
This difference provides the amount of work done on the jet and is given by:
(1)
Now, the work done by the engines is given by:
Now, using eqn (1):
![W_(jet) = 4.5* 10^(7) - 2.001* 10^(7) = 2.49* 10^(7) J](https://img.qammunity.org/2020/formulas/physics/college/zawuxmbs4jxxi8lt5az831be70qtkcbevm.png)