Answer:
The maximum number of fruits bag Harper can buy are 3.
Explanation:
Let there be x bags of fruits.
Let there be y boxes of chocolates
Cost of 1 bag of fruit = $4.75
So, cost of x bags = $4.75x
Cost of one box of crackers costs = $3.50
As per the given situation, the inequality forms:
![4.75x+3.50y\leq 15](https://img.qammunity.org/2020/formulas/mathematics/college/83roqtnxl2zswsowio74ogtlsw6yskoz6k.png)
So, the maximum number of bags of fruit Harper can buy, is when she buys no box of cracker.
So, putting y = 0 in above inequality , we have,
![4.75x+3.50(0)\leq 15](https://img.qammunity.org/2020/formulas/mathematics/college/pwtofnuxsyzg9lq7jbwd3oblha8eb6qnwt.png)
=>
![4.75x+0\leq 15](https://img.qammunity.org/2020/formulas/mathematics/college/ietwttzvckbehdilz9unppvak30o4s3e9j.png)
=>
![4.75x \leq 15](https://img.qammunity.org/2020/formulas/mathematics/college/oa46ux5oc2gyp1s3tltk97bgbh5b0br7yu.png)
rounding to 3.
Hence, the maximum number of fruits bag Harper can buy are 3.