Answer:
22800 tonne
Step-by-step explanation:
Given:
Length of the container, L = 240 m
Width of the container, B = 22 m
Depth inside the water, H = 10 m
Mass of the ship, m = 30000 tonnes
Now,
Total immersed volume of the ship = LBH = 240 × 22 × 10 = 52800 m³
From the Archimedes principle, we have
Total mass of the ship (i.e mass of the ship along with the load carried)
= Mass of the volume of water displaced by ship
= 52800 × Density of water
also,
Density of water = 1000 kg/m³
thus,
Total mass of the ship (i.e mass of the ship along with the load carried)
= 52800 × 1000 kg
also,
1 tonne = 1000 kg
thus,
Total mass of the ship (i.e mass of the ship along with the load carried)
= 52800 tonne
Therefore,
the load carried by the ship = Total mass of the ship - mass of ship
or
the load carried by the ship = 52800 - 30000 = 22800 tonne