Question

A small pad subjected to a shearing force is deformed at the top of the pad 0.12 in. The heigfit of the pad is 1.15 in. What is the shearing strain (rad) on the pad?

Answer 1

Shearing strain will be 0.1039 radian

Step-by-step explanation:

We have given change in length
`\Delta L=0.12inch`

Length of the pad L = 1.15 inch

We have to find the shearing strain

Shearing strain is given by

`\alpha =tan^(-1)(\Delta L)/(L)=tan^(-1)(0.12)/(1.15)=5.9571^(\circ)`

Shearing strain is always in radian so we have to change angle in radian

So
`5.9571* (\pi )/(180)=0.1039radian`