Question

A baseball thrown from the outfield is released form

shoulderheight at an initial velocity of 29.4 m/s at an initial
angle of30.0 with respect to the horizontal. What is the maximum
verticaldisplacement that the ball reaches during
itstrajectory?

Answer 1

`y_(max)=11m`

Step-by-step explanation:

The maximum vertical displacement that the ball reaches can be calculate using the following formula:

`v^(2)=v^(2) _(o)+2g(y-y_(o))`

At the highest point, its velocity becomes 0 because it stop going up and starts going down.

`0=(29.4sin(30))^(2) -2(9.8)y`

Solving for y

`y=((29.4sin(30))^(2))/(2(9.8)) =11m`