Question

A banked circular highway is designed for traffic moving

at60km/h. The radius of the curve is 200m. Traffic ismoving along
the highway at 40km/h on a rainy day. What isthe minimum
coefficient of friction between tires and road thatwill allow cars
to negotiate the turn without sliding off theroad?

Answer 1

0.063

Step-by-step explanation:

velocity of the car, v = 40 km/h = 11.11 m/s

radius, r = 200 m

Let the coefficient of friction is μ.

The coefficient of friction relates to the velocity on banked road is given by

`\mu =(v^(2))/(rg)`

where, v is the velocity, r be the radius of the curve road and μ is coefficient of friction.

By substituting the values, we get

`\mu =(11.11^(2))/(200* 9.8)`

μ = 0.063