Question

What is the minimum amount of energy required for an 80-

kgclimber carrying a 20- kg pack to climb Mt. Everest, 8850
mhigh?

Answer 1

minimum amount of energy required is 8.673 MJ

Step-by-step explanation:

given data

mass m1 = 80 kg

additional mass m2 = 20 kg

height = 8850 m

to find out

minimum amount of energy required

solution

we know here total mass is m = m1 + m2

m = 80 + 20

m = 100 kg

so now apply energy equation for climb high that is

energy = m×g×h ....................1

here m is mass and g is 9.8 and h is height

put here all value in equation 1

energy = m×g×h

energy = 100 ×9.8×8850

energy = 8673000 J

so minimum amount of energy required is 8.673 MJ