Question

What is the de Broglie wavelength for a proton (m = 1.67× 10^−27 kg) moving at a speed of 9.50 × 10^6 m/s? (h = 6.63 × 10^−34 J⋅s)

Answer 1

De broglie wavelength = 4.17 pm

Step-by-step explanation:

We have given mass of proton
`m=1.67* 10^(-27)kg`

Speed of proton v
`v=9.50* 10^(6)m/sec`

Plank's constant
`h=6.63* 10^(-34)J-s`

We have to find de broglie wavelength

De broglie wavelength is given by
`\lambda =(h)/(mv)=(6.63* 10^(-34))/(1.67* 10^(-27)* 9.5* 10^6)=4.17* 10^(-12)m=4.17pm`