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Calculate the rate at which body heat is conducted through the clothing of a skier in a steady- state process, given the following data: the body surface area is 1.80 m and the clothing is 1.00 cm thick; the skin surface temperature is 33.0 C and the outer surface of the clothing is at 1.00 C the thermal conductivity of the clothing is 0.040 W/m K

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Answer:

230.4W

Step-by-step explanation:

Heat transfer by conduction consists of the transport of energy in the form of heat through solids, in this case a jacket.

the equation is as follows


Q=(KA(T2-T1))/(L) \\

Where

Q=heat

k=conductivity=0.04

A=Area=1.8m^2

T2=33C

T1=1C

L=thickness=1cm=0.01m
Q=((0.04)(1.8m^2)(33-1))/(0.01m)

Q=230.4W

the skier loses heat at the rate of 230.4W

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