Question

A brittle intermetallics specimen is tested with a bending test. The specimen's width 0.45 in and thickness 0.20 in. The length of the specimen between supports 2.5 in. Determine the transverse rupture strength if failure occurs at a load 1200 lb.

Answer 1

250 kpsi

Step-by-step explanation:

Given:

Width of the specimen, w = 0.45 in

Thickness of the specimen, t = 0.20 in

length of the specimen between supports, L = 2.5 in

Failure load, F = 1200 lb

Now,

The transverse rupture strength
`\sigma_t=(1.5FL)/(wt^2)`

on substituting the respective values, we get

`\sigma_t=(1.5*1200*2.5)/(0.45*0.2^2)`

or

`\sigma_t=250,000\ psi\ =\ 250 kpsi`