Question

A 0.10- kg ball is thrown straight up into the air with

aninitial speed of 15m/s. Find the momentum of the ball (a) at
itsmaximum height and (b) halfway to its maximum height.

Answer 1

Answer:(a)0,(b)1.061 kg-m/s

Step-by-step explanation:

Given

mass of ball is 0.10 kg

Initial speed is 15 m/s

Maximum height reached by ball is h

`v^2-u^2=2as`

final velocity =0

`-\left ( 15\right )^2=-2* 9.81* s`

`s=(15^2)/(2* 9.81)=11.467 m`

thus momentum of ball at maximum height is 0 as velocity is zero

For halfway to maximum height

`v^2-u^2=2as_0`

where
`s_0=(11.467)/(2)`

`s_0=5.73 m`

`v^2=15^2-2* 9.81* 5.73`

v=10.61 m/s

Thus its momentum is

`mv=0.10* 10.61=1.061 kg-m/s`