Question

An Airbus A380 airliner can takeoff when its speed reaches 80 m/s. Suppose its engines together can produce an acceleration of 3 m/s. (a) How long does it take the plane to accelerate from 0 m/s to 80 m/s? (b) What is the distance traveled during this period?

Answer 1

(a). The time is 26.67 sec.

(b). The distance traveled during this period is 1066.9 m.

Step-by-step explanation:

Given that,

Speed = 80 m/s

Acceleration = 3 m/s

Initial velocity = 0

(a). We need to calculate the time

Using equation of motion

`v = u+at`

`t = (v-u)/(a)`

Put the value into the formula

`t = (80-0)/(3)`

`t =26.67\ sec`

The time is 26.67 sec.

(b). We need to calculate the distance traveled during this period

Using equation of motion

`s = ut+(1)/(2)at^2`

`s = 0+(1)/(2)*3*(26.67)^2`

`s =1066.9\ m`

The distance traveled during this period is 1066.9 m.

Hence, This is the required solution.