Question

X-rays are scattered from a target at an angle of 37.2° with the direction of the incident beam. Find the wavelength shift of the scattered x-rays.

Answer 1

`\Delta \lambda=4.94* 10^(-13)\ m`

Step-by-step explanation:

It is given that,

X-rays are scattered from a target at an angle of,
`\theta=37.2^(\circ)`

We need to find the wavelength shift of the scattered x-rays. The shift in wavelength is given by :

`\Delta \lambda=(h)/(mc)(1-cos\ \theta)`

h is the Planck's constant

m is the mass of electron

c is the speed of light

`\Delta \lambda=(6.63* 10^(-34))/(9.1* 10^(-31)* 3* 10^8)(1-cos(37.2))`

`\Delta \lambda=4.94* 10^(-13)\ m`

So, the wavelength shift of the scattered x- rays is
`4.94* 10^(-13)\ m`. Hence, this is the required solution.