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A team exerts a force of 10 N towards the south in a tug of war. The other, opposite team, exerts a force of 17 N towards the north. The net force is A. 27 N east. B. 7 N south C. 7 N north D. 27 N north

User Xella
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Answer:

Option C

Step-by-step explanation:

According to the question:

Force exerted by the team towards south, F = 10 N

Force exerted by the opposite team towards North, F' = 17 N

Net Force,
\vec{F_(net)} = \vec{F'} - \vec{F}


\vec{F_(net)} = \vec{F'} - \vec{F} = 17 - 10 = 7 N

Thus the force will be along the direction of force whose magnitude is higher

Therefore,


\vec{F_(net)} = 7 N towards North

User Leon Breedt
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