Question

Find the area of AABC. Where: A = (-3,3), B=(-4,1), C = (-6,0). W Area:

Answer 1

Answer:
`1.5\text{ square units}`

Explanation:

We know that the area of triangle with coordinates
`(x_1,y_1),(x_2,y_2)` and
`(x_3,y_3)` is given by :-

`\text{Area}=(1)/(2)|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|`

Given : The coordinates of ΔABC are A = (-3,3), B=(-4,1), C = (-6,0).

Then, the area of ΔABC will be :-

`\text{Area}=(1)/(2)|-3(1-0)+(-4)(0-3)+(-6)(3-1)|\\\\\Rightarrow\text{Area}=(1)/(2)|-3-4(-3)-6(2)|\\\\\Rightarrow\text{Area}=(1)/(2)|-3+12-12|\\\\\Rightarrow\text{Area}=(1)/(2)|-3|=(1)/(2)(3)=1.5`

Hence, the area of ΔABC=
`1.5\text{ square units}`