Question

Two tiny conducting sphere are identical and carry charges of -20 μC and +50 μC. They are separated by a distance of 2.50 cm. What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

Answer 1

Force between two spheres will be 14400 N

And as the both charges of opposite nature so force will be attractive

Step-by-step explanation:

We have given two conducting spheres of charges
`q_1=-20\mu C=-20* 10^(-6)C\ and\ q_2=50\mu C=50* 10^(-6)C`

Distance between the spheres = 2.5 cm =0.025 m

According to coulombs law we know that force between two charges is given by
`F=(1)/(4\pi \varepsilon _0)(q_1q_2)/(r^2)=(Kq_1q_2)/(r^2)=(9* 10^9* 20* 10^(-6)* 50* 10^(-6))/(0.025^2)=14400N`

As the both charges of opposite nature so force will be attractive