Question

When glucose is consumed, it reacts with oxygen in the body to produce carbon dioxide, water, and energy. How many grams of carbon dioxide would be produced if 45g of C6H12O completely reacted with oxygen

Answer 1

If 45g of glucose reacts with oxygen, 66.015 grams of carbon dioxide would be produced. This calculation is based on converting the mass of glucose to moles, using the stoichiometry of the balanced chemical equation, and then calculating the mass of CO2 produced.

Step-by-step explanation:

When glucose (which has the chemical formula C6H12O6) is consumed, it reacts with oxygen to produce carbon dioxide, water, and energy. The chemical equation for this reaction is C6H12O6 + 6 O2 → 6 CO2 + 6 H2O. Given that 45g of C6H12O6 completely reacts with oxygen, we need to calculate the mass of carbon dioxide produced from this reaction.

To do this, we first need to determine the molar mass of glucose, which is 180.16 g/mol. This means that 1 mole of glucose weighs 180.16 grams. We can then find out how many moles of glucose 45g represents by dividing 45g by 180.16 g/mol, which gives us 0.25 mol of glucose.

According to the chemical equation, 1 mole of glucose produces 6 moles of CO2. Therefore, 0.25 moles of glucose would produce 0.25 × 6 = 1.5 moles of CO2. The molar mass of CO2 is 44.01 g/mol, so the mass of CO2 produced by 0.25 moles of glucose is 1.5 moles × 44.01 g/mol, resulting in 66.015 grams of CO2. So, if 45g of C6H12O6 completely reacted with oxygen, 66.015 grams of CO2 would be produced.

Answer 2

There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen

Step-by-step explanation:

Step 1 : Balance the formula

Oxidation of glucose can be shown in the following equation :

C6H12O6 + 6 O2 → 6 CO2 + 6H2O

This means that for 1 mole glucose that react there will react 6 moles of O2, to form 6 moles of CO2 and 6 moles of H2O

Step 2: Calculating moles

mole glucose = 45g / Molar mass glucose

⇒ Molar mass = 6*12 + 12*1 + 6*16 = 72 + 12 + 96 = 180g/mole

⇒ mole glucose = 45g / 180g/mole

⇒mole glucose = 0.25 mole

Since 1 mole of glucose is used to form 6 moles of CO2

0.25 mole of glucose is used to form 1.5 moles of CO2

Step 3 : Calculating mass of Carbon dioxide

Mass of CO2 = 1.5 moles of CO2 * 44 g/mole

mass of CO2 = 66g

There will be produced 66g of CO2 if 45g of glucose completely reacted with oxygen