Question

A series RLC circuit has a resistance of 44.0 Ω and an impedance of 71.0 Ω. What average power is delivered to this circuit when ΔVrms = 210 V?

Answer 1

power = 384.92 W

Step-by-step explanation:

given data

resistance = 44.0 Ω

impedance = 71 Ω

ΔVrms = 210 V

to find out

average power

solution

we know here power formula that is

power =
`(V^2rms)/(impedance)`cos∅ .........1

we know here cos∅ =
`(resistance)/(impedance)`

cos ∅ =
`(44)/(71)` = 0.6197

so from equation 1

power =
`(210^2)/(71)` × 0.6197

power = 384.92 W