Question

A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her piston is 19.0 cm in diameter, what is the diameter of the football players' piston?

Answer 1

The diameter of the piston of the players equals 55.136 cm.

Step-by-step explanation:

from the principle of transmission of pressure in a hydraulic lift we have

`(F_(1))/(A_(1))=(F_(2))/(A_(1))`

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

`(57.0* 9.81)/((\pi * (19.0)^(2))/(4))=(4* 120* 9.81)/((\pi * D_(2)^(2))/(4))`

Solving for
`D_(2)` we get

`D_(2)^(2)=(4* 120)/(57)* 19^(2)\\\\\therefore D_(2)=\sqrt{(4* 120)/(57)}* 19\\\\D_(2)=55.136cm`