Final answer:
The magnitude of the electric force on one of the masses is 102.71 N. The initial acceleration of the mass is 51.36 m/s^2.
Step-by-step explanation:
PART A:
To find the magnitude of the electric force on one of the masses, we can use Coulomb's Law.
The formula for the magnitude of the electric force is:
F = k * (|q1| * |q2|) / r^2
where F is the force, k is the Coulomb's constant (9 x 10^9 Nm^2/C^2), |q1| and |q2| are the magnitudes of the charges (9.6 μC), and r is the distance between the charges (1.1 m).
Plugging in the values:
F = (9 x 10^9 Nm^2/C^2) * (9.6 μC * 9.6 μC) / (1.1 m)^2
F = 102.71 N
The magnitude of the electric force on one of the masses is 102.71 N.
PART B:
To find the initial acceleration of the mass when it is released and allowed to move, we can use Newton's second law.
The formula for the acceleration is:
a = F / m
where a is the acceleration, F is the force (102.71 N), and m is the mass (2.0 kg).
Plugging in the values:
a = 102.71 N / 2.0 kg
a = 51.36 m/s^2