Final answer:
To calculate the magnitude of the charge that creates a 4.70 N/C electric field at a point 3.70 m away, we can use Coulomb's law. The magnitude of the charge is approximately 2.58 * 10^(-6) C.
Step-by-step explanation:
To calculate the magnitude of the charge that creates a 4.70 N/C electric field at a point 3.70 m away, we can use Coulomb's law. Coulomb's law states that the electric field is equal to the force exerted by the charge, divided by the distance squared. The equation is:
E = k * (q / r^2)
where E is the electric field, q is the charge, r is the distance, and k is the electrostatic constant.
In this case, we are given the electric field (4.70 N/C) and the distance (3.70 m). Plugging these values into the equation, we can solve for the magnitude of the charge:
4.70 N/C = k * (q / (3.70 m)^2)
Simplifying the equation, we have:
q = (E * r^2) / k
q = (4.70 N/C * (3.70 m)^2) / k
Using the given values of the electrostatic constant and performing the calculation, we find that the magnitude of the charge is approximately 2.58 * 10^(-6) C.