Question

A particle of charge Q is fixed at the origin of an xy coordinate system. At t = 0 a particle (m = 0.727 g, q = 2.73 µC is located on the x axis at x = 19.3 cm, moving with a speed of 49.2 m/s in the positive y direction. For what value of Q will the moving particle execute circular motion? (Neglect the gravitational force on the particle.)

Answer 1

Q = 12.466μC

Step-by-step explanation:

For the particle to execute a circular motion, the electrostatic force must be equal to the centripetal force:

`Fe = (K*q*Q)/(r^(2)) = (m*V^(2))/(r)`

Solving for Q:

`Q = (m*V^(2)*r)/(K*q)`

Taking special care of all units, we can calculate the value of the charge:

Q = 12.466μC