An article reports "attendance increased 5% this year, to 4948." What was the attendance before the increase? (Round your answer to the nearest whole number.)

Question

asked Jun 23, 2020 135k views

1 Answer

Chetan Paliwal · Answer 1 · 2020-06-28T11:40:19+0000

Answer: The attendance before the increase was 4712.

Explanation:

Let the attendance before the increase be 'x'.

Rate of increment = 5%

so, Attendance after increment becomes

$(100+5)/(100)* x = 4948\\\\(105)/(100)* x=4948\\\\1.05* x=4948\\\\x=(4948)/(1.05)\\\\x=4712.38\\\\x=4712$

Hence, the attendance before the increase was 4712.