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Using direct substitution, verify that y(t) is a solution of the given differential equations 17-19. Then using the initial conditions, determine the constants C or c1 and c2.

17. y ′′ + 4y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1 cos 2t + c2 sin 2t

18. y ′′ − 5y ′ + 4y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1et + c2e4t

19. y ′′ + 4y ′ + 13y = 0, y(0) = 1, y ′ (0) = 0, y(t) = c1e-2t cos 3t + c2e-3tsin 3t

User Rang
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1 Answer

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Answer:

17. C1 = 1 and C2 = 0

18. C1 = 4/3 and C2 = -1/3

Explanation:

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Using direct substitution, verify that y(t) is a solution of the given differential-example-1
Using direct substitution, verify that y(t) is a solution of the given differential-example-2
Using direct substitution, verify that y(t) is a solution of the given differential-example-3
User Balaji Venkatraman
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5.7k points
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