Question

–27x^6b^9 as a cube of a monomial

Answer 1

`\bf -27x^6b^9~~ \begin{cases} -27=&-3^3\\ x^6=&x^(2\cdot 3)\\ &(x^2)^3\\ b^9=&b^(3\cdot 3)\\ &(b^3)^3 \end{cases}\implies (-3)^3(x^2)^3(b^3)^3\implies (-3x^2b^3)^3`