Question

Calculate The water pressure at the bottom of the Marianas Trench is approxi mately 1,100 kPa. With how much force would the water pressure at the bottom of the Marianas Trench push on a fish with a surface area of 0.50 m^2?

Answer 1

The water pressure at the bottom of the Marianas Trench would exert a force of 550,000 Newtons on a fish with a surface area of 0.50 m^2.

Step-by-step explanation:

The water pressure exerted on a fish at the bottom of the Marianas Trench can be determined by using the formula for pressure (P), which is force (F) divided by area (A). Given the pressure at the bottom of the trench is approximately 1,100 kPa and the surface area of the fish is 0.50 m2, the force can be calculated using the equation F = P x A. By inserting the given values, we get F = 1,100,000 Pa x 0.50 m2 = 550,000 N. Therefore, the water pressure would push on the fish with a force of 550,000 Newton.

Answer 2

Force, F = 550000 N

Step-by-step explanation:

Given that,

Pressure at the bottom of the Marianas Trench,
`P=1100\ kPa=11* 10^5\ Pa`

Surface area,
`A=0.5\ m^2`

We need to find the force with which the water pressure at the bottom of the Marianas Trench push on a fish. Mathematically, the pressure is given by :

`P=(F)/(A)`

`F=P* A`

`F=11* 10^5\ Pa* 0.5\ m^2`

F = 550000 N

So, the force with which the water pressure at the bottom of the Marianas Trench push on a fish is 550000 N. Hence, this is the required solution.