Answer: The proof is done below.
Step-by-step explanation: Given that the square matrix A is called orthogonal provided that

We are to show that the determinant of such a matrix is either +1 or -1.
We will be using the following result :

Given that, for matrix A,

Taking determinant of the matrices on both sides of the above equation, we get
![|A^T|=|A^(-1)|\\\\\Rightarrow |A|=(1)/(|A|)~~~~~~~~~~~~~~~~~~~~[\textup{since A and its transpose have same determinant}]\\\\\\\Rightarrow |A|^2=1\\\\\Rightarrow |A|=\pm1~~~~~~~~~~~~~~~~~~~~[\textup{taking square root on both sides}]](https://img.qammunity.org/2020/formulas/mathematics/college/izfu74xg5j46dr8k244dlhvjde37f96v5p.png)
Thus, the determinant of matrix A is either +1 or -1.
Hence showed.