Question

What are the sign and magnitude of a point charge that produces an electric potential of −2.36 V at a distance of 2.93 mm?

Answer 1

q = -7.691 ×
`10^(-13)` C

so magnitude of charge is 7.691 ×
`10^(-13)` C

and negative sign mean charge is negative potential

Step-by-step explanation:

given data

electric potential = −2.36 V

distance = 2.93 mm = 2.93 ×
`10^(-3)` m

to find out

What are the sign and magnitude of a point charge

solution

we know here that electric potential due to charge is

V =
`k(q)/(r)` ..............................1

here k is coulomb force that is 8.99 ×
`10^(9)` Nm²/C² and r is distance and q is charge and V is electric potential

put here all value we get q in equation 1

V =
`k(q)/(r)`

-2.36 =
`8.99*10^(9) (q)/(2.93*10^(-3))`

q = -7.691 ×
`10^(-13)` C

so magnitude of charge is 7.691 ×
`10^(-13)` C

and negative sign mean charge is negative potential