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What is the magnitude of the electric force between two point charges with Q1 = -1.5 C and Q2 = 0.8 C at a distance of 1 km?

User Skeletank
by
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1 Answer

4 votes

Answer:

F = -10800 N

Step-by-step explanation:

Given that,

Charge 1,
q_1=-1.5\ C

Charge 2,
q_2=0.8\ C

Distance between the charges,
d=1\ km=10^3\ m

We need to find the electric force acting between two point charges. Mathematically, it is given by :


F=k(q_1q_2)/(d^2)


F=-9* 10^9* (1.5* 0.8)/((10^3)^2)

F = -10800 N

So, the magnitude of electric force between two point charges is 10800 N. Hence, this is the required solution.

User Diane
by
7.6k points

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