Answer:
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.
Step-by-step explanation:
u = Object distance
v = Image distance
f = Focal length = 35
m = Magnification = 2.5
![m=-(v)/(u)\\\Rightarrow 2.5=-(v)/(u)\\\Rightarrow v=-2.5 u](https://img.qammunity.org/2020/formulas/physics/college/xsjsy886n3bfmtl7vqclvuq176gzum5nut.png)
Lens equation
![(1)/(f)=(1)/(u)+(1)/(v)\\\Rightarrow (1)/(35)=(1)/(u)+(1)/(-2.5u)\\\Rightarrow (1)/(35)=(3)/(5u)\\\Rightarrow u=21\ cm](https://img.qammunity.org/2020/formulas/physics/college/34psgvlpvu056xpgkpaksjwcv2ciy1p4gs.png)
![v=-2.5* 21=-52.5\ cm](https://img.qammunity.org/2020/formulas/physics/college/3sw20etgea8fzdfcnksddtvb2bpzv0zm1g.png)
Image distance is -52.5 cm
Image is virtual and forms on the same side of the lens and upright image is formed.