Answer:
Momentum of bullet
![P = 2.72 kg m/s](https://img.qammunity.org/2020/formulas/physics/college/f7v4naynapytwcs96f6mozbdupm670wozb.png)
momentum of baseball
![P = 8 kg m/s](https://img.qammunity.org/2020/formulas/physics/college/g02gr7e3c08b4xdzlbm2bx4s1fd58cznzi.png)
Step-by-step explanation:
As we know that momentum is defined as the product of mass and velocity
here we know that
mass of the bullet = 8 gram
velocity of bullet = 340 m/s
momentum of the bullet is given as
![P = mv](https://img.qammunity.org/2020/formulas/physics/high-school/sf82jq0v1hccf3tbythbvi54tvskpd6rhs.png)
![P = ((8)/(1000))(340)](https://img.qammunity.org/2020/formulas/physics/college/1ehy2b8bnklu68bad1fr6s1fuir2l48f77.png)
![P = 2.72 kg m/s](https://img.qammunity.org/2020/formulas/physics/college/f7v4naynapytwcs96f6mozbdupm670wozb.png)
Now we have
mass of baseball = 0.2 kg
velocity of baseball = 40 m/s[/tex]
momentum of baseball is given as
![P = (0.2)(40)](https://img.qammunity.org/2020/formulas/physics/college/sxwwknfp4252wuznj2r71dvymdkjd1oeip.png)
![P = 8 kg m/s](https://img.qammunity.org/2020/formulas/physics/college/g02gr7e3c08b4xdzlbm2bx4s1fd58cznzi.png)