Question

For a motor purchased for a tank project, it claims that at 12V it produces 6000 RPM. This motor is attached to a 50:1 gear reduction gearbox. The output of this gearbox is attached to a 2.5" wheel. Determine the speed of the tank under these conditions in miles/hour (mph).

Answer 1

0.889 mph

Step-by-step explanation:

Given:

Voltage = 12 V

RPM produced, N₁ = 6000

Gear reduction gearbox, G = 50:1

Diameter of the wheel = 2.5" = 2.5 × 0.0254 = 0.0635 m

Now,

The output speed =
`\frac{N_1}{\textup{G}}=(6000)/(50)` = 120 RPM

Thus,

The speed, v =
`(\pi DN_2)/(60)`

on substituting the respective values, we get

v =
`(\pi*0.0635*120)/(60)`

or

v = 0.39878 m/s

Also,

1 m/s = 2.23 mph

thus,

v = 0.39878 × 2.23 = 0.889 mph