Question

What is the force of gravity between two 15,000 kg cement trucks that are parked 3 meters apart? How does this force compare with the weight of one of the trucks?

Answer 1

`(W)/(F) = 8.8*10^7`

Step-by-step explanation:

According to newton's law of gravitation

`F=G(m_1* m_2)/(r^2)`

here m_1=m_2=15000 kg

r= 3 meters and G= 6.67
`6.67*10^(-11)`

putting values we get

`F= 6.67*10^(-11)(15000^2)/(3^2)`

solving the above equation we get

Force of gravitation F=
`1.6675* 10^(-3)` newton

weight of the one of the truck W = mg= 15000×9.81 N

=147000 N

therefore
`(W)/(F) = (147000)/(1.66*10^(-3))`

=8.8×10^{7)