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While skydiving, your parachute opens and you slow from 50.0 m/s to 8.0 m/s in 0.75 s . Determine the distance you fall while the parachute is opening.

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Answer:

21.75 m

Step-by-step explanation:

t = Time taken for the car to slow down = 0.75 s

u = Initial velocity = 50 m/s

v = Final velocity = 8 m/s

s = Displacement

a = Acceleration

Equation of motion


v=u+at\\\Rightarrow a=(v-u)/(t)\\\Rightarrow a=(8-50)/(0.75)\\\Rightarrow a=-56\ m/s^2

Acceleration is -56 m/s²


v^2-u^2=2as\\\Rightarrow s=(v^2-u^2)/(2a)\\\Rightarrow s=(8^2-50^2)/(2* -56)\\\Rightarrow s=21.75\ m

The distance covered in the 0.75 seconds is 21.75 m

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