Question

An airplane heading due east has a velocity of 210 miles per hour. A wind is blowing from the north at 38 miles per hour. What is the resultant velocity of the airplane? (Assume that east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.)

Answer 1

The resultant velocity of the airplane is 213.41 m/s.

Explanation:

Given that,

Velocity of an airplane in east direction,
`v_1=210\ mph`

Velocity of wind from the north,
`v_2=38\ mph`

Let east lies in the direction of the positive x-axis and north in the direction of the positive y-axis.

We need to find the resultant velocity of the airplane. Let v is the resultant velocity. It can be calculated as :

`v=√(v_1^2+v_2^2)`

`v=√((210)^2+(38)^2)`

v = 213.41 m/s

So, the resultant velocity of the airplane is 213.41 m/s. Hence, this is the required solution.