54.9k views
1 vote
(a) If 15 kW of power from a heat reservoir at 500 K is input into a heat engine with an efficiency of 37%, what is the power output? (b) What is the temperature of the cold reservoir?

1 Answer

4 votes

Answer:

(A) Power output will be 5.55 KW (b) lower temperature will be 315 K

Step-by-step explanation:

We have given efficiency of heat engine
\eta =37% = 0.37

Input power = 15 KW

Temperature of heat reservoir
T_H=500K

(A) We know that
\eta =(output)/(input)

So [text]0.37=\frac{output}{15}[text]

Output = 5.55 KW

(B) We also know that [text]\eta =1-\frac{T_L}{T_H}0.37=\frac{output}{15}[text], here
T_L is lower temperature and
T_H is higher temperature

So
0.37=1-(T_L)/(T_H)


0.37=1-(T_L)/(500)


T_L=315K

User Patryk Godowski
by
9.1k points