Question

If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in meters.

Answer 1

Height, H = 25.04 meters

Step-by-step explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

`H=ut+(1)/(2)at^2`

Here, a = g

`H=(1)/(2)gt^2`

`H=(1)/(2)* 9.8* (2.261)^2`

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.