Question

Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitude of the force that one particle exerts on the other?

Answer 1

Force, F = −229.72 N

Step-by-step explanation:

Given that,

First charge particle,
`q_1=-6.29* 10^(-6)\ C`

Second charged particle,
`q_2=5.23* 10^(-6)\ C`

Distance between charges, d = 0.0359 m

The electric force between the two charged particles is given by :

`F=k(q_1q_2)/(d^2)`

`F=9* 10^9* (-6.29* 10^(-6)* 5.23* 10^(-6))/((0.0359)^2)`

F = −229.72 N

So, the magnitude of force that one particle exerts on the other is 229.72 N. Hence, this is the required solution.