204k views
3 votes
Raindrops fall 1.59 x 10^3 m from a cloud to the ground. If they were not slowed by air resistance, how fast would the drops be moving when they struck the ground?

User Navnav
by
7.9k points

1 Answer

3 votes

Answer:

18 seconds

Step-by-step explanation:

s = Displacement = 1.59×10³ m

a = Acceleration due to gravity = 9.81 m/s²

u = Initial velocity = 0

v = Final velocity

t = Time taken

Equation of motion


s=ut+(1)/(2)at^2\\\Rightarrow 1590=0* t+(1)/(2)* 9.81* t^2\\\Rightarrow t=\sqrt{(1590* 2)/(9.81)}\\\Rightarrow t=18\ s

Time taken by the raindrop to reach the ground neglecting air resistance is 18 seconds

User Roger Sanders
by
8.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.