Question

A ball is thrown upward at time t=0 from the ground with an initial velocity of 4 m/s (~ 9 mph). Assume that g = 10 m/s^2. What is the greatest height (in meters) reached by the ball?

Answer 1

The greatest height reached by the ball is 0.8 m.

Step-by-step explanation:

Given that,

Initial velocity = 4 m/s

We need to calculate the greatest height reached by the ball

Using equation of motion

`v^2=u^2+2gh`

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

`0=4^2+2*(-10)* h`

`h =(16)/(20)`

`h =0.8\ m`

Hence, The greatest height reached by the ball is 0.8 m.