Question

A jetliner rolls down the runway with constant acceleration from rest, it reaches its take off speed of 250 km/h in 1 min. What is its acceleration? Express in km/h^2, does this result make sense?

Answer 1

Acceleration,
`a=14970.05\ km/h^2`

Step-by-step explanation:

Given that,

Initially, the jetliner is at rest, u = 0

Final speed of the jetliner, v = 250 km/h

Time taken, t = 1 min = 0.0167 h

We need to find the acceleration of the jetliner. The mathematical expression for the acceleration is given by :

`a=(v-u)/(t)`

`a=(250)/(0.0167)`

`a=14970.05\ km/h^2`

So, the acceleration of the jetliner is
`14970.05\ km/h^2`. Hence, this is the required solution.